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Question

If fn(x)=loglogloglogx(log is repeated ntimes), then [xf1(x)f2(x)fn(x)]1dx=

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Solution

(1xf1(x)f2(x)..........fn(x))dxletfn(x)=tthen(1fn1(x).......f1(x))×(1x)dx=dtI=(1t)dt=logt+C=logfn(x)+C=fn+1(x)+C


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