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Question

If f:RR and g:R are defined by f(x)=2x+3 and g(x)=x2+7, then the values of x such that g(f(x))=8 are


A

1, 2

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B

-1, 2

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C

-1, -2

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D

1, -2

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Solution

The correct option is C

-1, -2


f(x)=2x+3 and g(x)=x2+7
g(f(x))=8f(x)22+7=8(2x+3)2+7=84x2+9+12x+7=84x2+12x+16=8x2+3x+4=2x2+3x+2=0(x+2)(x+1)=0x=1,2


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