If f-R- R-g-R- R be two given functions then f x -2min f x -g x -0 equals

The correct option is D f( x ) g( x ) | g( x ) f( x ) | We have, f( x ) =2min{ f( x ) g( x ) ,0 } nbsp; = 0 amp; f( x ) gt;g( x ) nb ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Monotonically Increasing Functions

If f:R→ R,g...

Question

If $f : R \to R, g : R \to R$ be two given functions then $f (x) = 2 min {f (x) - g (x), 0}$ equals

f (x) + g (x) - | g (x) - f (x) |

No worries! We‘ve got your back. Try BYJU‘S free classes today!

f (x) + g (x) + | g (x) - f (x) |

No worries! We‘ve got your back. Try BYJU‘S free classes today!

f (x) - g (x) + | g (x) - f (x) |

No worries! We‘ve got your back. Try BYJU‘S free classes today!

f (x) - g (x) - | g (x) - f (x) |

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

f : R \to R, g : R \to R

f (x) = 2 min {| f (x) - g (x) |, 0}

f (x) = e^{x}, g (x) = \log_{e} x

f (x) = x^{2}, g (x) = \cos x

f (x) = | x |, g (x) = \sin x

f (x) = x + 1, g (x) = e^{x}

f (x) = \sin^{- 1} x, g (x) = x^{2}

f (x) = x + 1, g (x) = \sin x

f (x) = x + 1, g (x) = 2 x + 3

f (x) = c, c \in R, g (x) = \sin x^{2}

f (x) = x^{2} + 2, g (x) = 1 - \frac{1}{1 - x}

If f(x) is divided by g(x), g(x) ≠ 0 , then there exist two polynomials q(x) and r(x) such that

f : R^{+} \to R^{+}, f (x) = x^{2} + 2

g : R^{+} \to R^{+}, g (x) = \sqrt{x + 1}

(f + g) (x)

Join BYJU'S Learning Program