if f:R→R is an invertible function such that f(x) and f−1(x) are symmetric about the line y=−x, then
A
f(x) is odd
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B
f(x) and f−1(x) may not be symmetric about the line y=x
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C
f(x) may not be odd
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D
None of these
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Solution
The correct option is Df(x) is odd From the given condition we know that f(x) is invertible. Since it is symmetric about y=−x, f(−x)=−f(x) Thus, f(x) is odd. Hence, option 'A' is correct.