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Question

If f:RR satisfies f(x)f(y)xy3 and g(x)=f(x+f(x)), then the value of g(1) is

A
Cannot be determined
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B
1
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C
1
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D
0
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Solution

The correct option is D 0
|f(x)f(y)||xy|3
|f(x)f(y)||xy||xy|2
Taking limxyon both sides
limxy|f(x)f(y)||xy|limxy|xy|2
|f(x)|0
f(x)=0 xR
g(x)=f(x+f(x))g(x)=f(x+f(x)).(1+f(x))
f(x)=0
g(x)=0 xR
g(1)=0

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