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Question

If f(t)=4t23t+6 find
(i) f(0),
(ii) f(4),
(iii) f(-5)

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Solution

f(t)=4t23t+6(i) f(0)=4×023×0+6=00+6=6(ii) f(4)=4×423×4+6=6412+6=58(iii) f(5)=4×(5)23×(5)+6=100+15+6=121


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