If $f (t) = 4 t^{2} - 3 t + 6$ find
(i) f(0),
(ii) f(4),
(iii) f(-5)

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Solution

$f (t) = 4 t^{2} - 3 t + 6 (i) f (0) = 4 \times 0^{2} - 3 \times 0 + 6 = 0 - 0 + 6 = 6 (i i) f (4) = 4 \times 4^{2} - 3 \times 4 + 6 = 64 - 12 + 6 = 58 (i i i) f (- 5) = 4 \times (- 5)^{2} - 3 \times (- 5) + 6 = 100 + 15 + 6 = 121$

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