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Question

If f(θ)=2(sec2θ+cos2θ),  then its
value always
  1. 4>f(θ)>2
  2. f(θ)4
  3. f(θ)<2
  4. f(θ)=2


Solution

The correct option is B f(θ)4
f(θ)=2(sec2θ+cos2θ)f(θ)=2(secθcosθ)2+4secθcosθ 
f(θ)=2(secθcosθ)2+44 

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