If $f (x + 1) = 3 x - 9$ , then what will be the value of $f (x^{2} - 1)$ ?

3 x^{2} - 9

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3 x^{2} - 15

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x^{2} - 10

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3 x^{2} - 10

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Solution

The correct option is B $3 x^{2} - 15$
Replace $x \to x - 1 \Rightarrow f (x) = 3 x - 12$
$∴ f (x^{2} - 1) = 3 (x^{2} - 1) - 12$

$= 3 x^{2} - 15$ .

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