The correct option is A It is continuous and differentiable in 0<x<π2
f(x)=1+[cosx]x in 0<x≤π2
in 0<x≤π2,cosx∈[0,1)
⇒f(x)=1+0⋅x=1
Since, f(x) is a constant function , it is continuous as well as differentiable in the entire interval.
Clearly, f(0)=1.
Also, x=1 lies in the given interval 0<x≤π2
Hence, f(x) is differentiable at x=1