If f(x)=1+x+x22+....+x200200
, then f '(1) is equal to
A
1200
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B
200
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C
100
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D
\N
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Solution
The correct option is B 200 Given that f(x)=1+x+x22+....+x200200∴f'(x)=ddx(1+x+x22+....+x200200}⇒f'(x)=0+1+2x2+....+200x199200∴f'(1)=0+1+1+....+1(200times)⇒f'(1)=200