If $f (x) = 2 x + 1$ and $g (x) = x - 3$ find $f o g$ .

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Solution

$f (x) = 2 x + 1$

$g (x) = x - 3$

$f o g = 2 (x - 3) + 1$

$= 2 x - 6 + 1$

$f o g = 2 x - 5$

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