If $f (x) = 2 x^{2} - 3 x - 1$ , then find $f (x + 2)$ .

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Solution

$f (x) = 2 x^{2} - 3 x - 1 f (x + 2) = 2 {(x + 2)}^{2} - 3 (x + 2) - 1 = 2 (x^{2} + 4 + 4 x) - 3 x - 6 - 1 = 2 x^{2} + 8 + 8 x - 3 x - 7 = 2 x^{2} + 5 x + 1$

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f (x) = 2 x^{2} + 3 x + 2

f (2)

f (x + 1) = 2 x^{2} - 3 x + 1

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f (x + 3) = 2 x^{2} - 3 x + 1

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