If $f (x) = 2 x^{2} + 3 x + 2$ then find the value of $f (2)$

Open in App

Solution

$f (x) = 2 x^{2} + 3 x + 2$

$f (2) = 2 (2)^{2} + 3 (2) + 2$

$= 8 + 6 + 2$

$= 16$

Suggest Corrections

Similar questions

f (x + 1) = 2 x^{2} - 3 x + 1

f (x + 2)

f (x) = 2 x^{2} - 3 x - 1

f (x + 2)

f (x + 1) = 2 x^{2} - 3 x - 1

f (0)

f (x + 2)

f (x) = x^{2} - 3 x + 1

f (2 α) = 2 f (α)

α

f (x) = 3 x^{- 2}

f (2)

Join BYJU'S Learning Program