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Question

If f(x)=2x3+3x211x+6, find f(0)

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Solution

In the given polynomial f(x)=2x3+3x211x+6, substitute x=0 as shown below:

f(0)=(2×03)+(3×02)(11×0)+6=(2×0)+(3×0)(11×0)+6=0+00+6=6

Hence, f(0)=6.



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