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Question

If f(x)=2x3+3x211x+6, find f(3)

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Solution

In the given polynomial f(x)=2x3+3x211x+6, substitute x=3 as shown below:

f(3)=(2×(3)3)+(3×(3)2)(11×(3))+6=(2×(27))+(3×9)+33+6=54+27+33+6
=54+66=12

Hence, f(3)=12.


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