wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If f(x)=|2x3+x7|, then

A
f(x)=2x3+x7 when 2x3+x70
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
f(x)=2x3+x7 when 2x3+x70
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
f(x)=72x3x when 2x3+x7<0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
f(x)=72x3x when 2x3+x7>0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C f(x)=72x3x when 2x3+x7<0
f(x)={ 2x3+x7 ,2x3+x70(2x3+x7) ,2x3+x7<0
f(x)={2x3+x7 ,2x3+x7072x3x ,2x3+x7<0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon