If f(x)=2x4−7x3+ax+b is divisible by (x−1) and (x−2), then (a,b)=
A
(19,−14)
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B
(19,14)
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C
(−19,14)
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D
(−19,−14)
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Solution
The correct option is D(19,−14) f(x) is divisible by (x−1) and (x−2) So, f(1)=0 and f(2)=0 f(1)=2−7+a+b=a+b−5=0 ⇒a+b=5 f(2)=32−56+2a+b=2a+b−24=0 ⇒2a+b=24 From the above two relations, we have