If f(x+2y, x-2y)=xy, then f(x, y) equals
Let x + 2y = p x – 2y = q Solving we got x=p+q2 y=p−q2∴f(p,q)=p2−q28F(x,y)=x2−y28
If f(x+2y,x−2y)=xy, then f(x,y) equals