If f (x) = 3x − 2 , g(x) = 2x + k and f o g = g o f , then find the value of k.
A
-2
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B
2
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C
1
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D
-1
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Solution
The correct option is D -1 Given: f (x) = 3x − 2 and g(x) = 2x + k
Now, f o g(x) = f (g(x))
= f (2x +k)
= 3(2x +k)−2 ⇒ f o g(x) = 6x + 3k −2
Also, g o f (x) = g (f(x))
= g(3x −2)
= 2(3x −2)+k ∴ g o f (x) = 6x - 4 + k
But, f o g = g o f ⇒ 6x + 3k −2 = 6x - 4 + k ⇒ 2k = -2 ⇒ k = -1
Hence, value of k is -1.