Question

If $f\left(x\right)=3x^2-x$ where $x=1$ and $\delta x=0.02$ then $\delta f=$

• A. $0.1012$
• B. $1.012$
• C. $0.101$
• D. $0.1$

Answer 1

The correct option is D $0.1$

Given that,

$f\left(x\right)=3x^2-x$

$x=0$

$\delta f=0.02$

$\delta f=\left(6x-1\right)\delta f$

$=5\times 0.02$

$=0.1$

Then,

Option $D$ is correct answer.