If fx-3x-5 and gx- x 2 -1- then f- g x 2 -1 is equal to

The correct option is B 3 x ^ 4 6 x ^ 2 +5 f(x)=3x+5 and g(x)=x^2 1 ∴ f∘ g( x ^ 2 1 ) =f[g( x ^ 2 1 ) ]=f[ ( x ^ 2 1 ) #160;^ 2 ...

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Composite Function

If fx=3x+5 ...

Question

If $f (x) = 3 x + 5$ and $g (x) = x^{2} - 1$ , then $(f \circ g)$ $(x^{2} - 1)$ is equal to

3 x^{4} - 3 x + 5

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3 x^{4} - 6 x^{2} + 5

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6 x^{4} + 3 x^{2} + 5

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6 x^{4} - 6 x + 5

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3 x^{2} + 6 x + 4

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Solution

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Similar questions

f (x) = c o t^{- 1} (\frac{3 x - x^{3}}{1 - 3 x^{2}}), g (x) = c o s^{- 1} (\frac{1 - x^{2}}{1 + x^{2}})

f (x) = g (x)

x = \frac{\sqrt{25 - 10 \sqrt{5}}}{5}

s i n 18^{o} = \frac{\sqrt{5} - 1}{4}

f (x) = 3 x - 5

g (x) = x^{2} + 1, f [g (x)] =

f (x) = \sqrt{x}

g (x) = \frac{3 x^{2} - x^{6}}{1 - 3 x^{4}}

h (x) = tan x,

(g \circ f \circ h) (\frac{π}{3})

(1 + \frac{1}{2} x + \frac{1}{\sqrt{3}} x^{2})

(5 - \frac{2}{3} + \sqrt{3} x^{2})

(4 - \frac{1}{3} x - 2 \sqrt{3} x^{2})

1 + \frac{1}{6} x + \frac{10}{\sqrt{3}} x^{2}

f (x) = 3 x^{2} - 5

g (x) = \frac{x}{x^{2} + 1}

(g o f) (x)

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