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Quadratic Formula

If fx=4 x3-6 ...

Question

If f(x) = $4 x^{3} - 6 x^{2} + 5 x - 1$ and $α, β$ and $γ$ are its zeros, then $α β γ$ =

A

3

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B

5

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C

-3

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D

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Solution

The correct option is D

$α β γ$ = $- \frac{d}{a} \to$ $α β γ$ = $\frac{1}{4}$

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Similar questions

α

β

are zeroes of polynomial

6 x^{2} - 5 x + k a n d α - β = \frac{1}{6}

α

β

are the zeros of the polynomial

f (x) = 6 x^{2} - 3 - 7 x

(α + 1) (β + 1)

α, β

are the zeroes of

f (x) = x^{2} - 5 x + b

α - β = 1

b

α

β

are the zeros of the quadratic polynomial

f (x) = 6 x^{2} - x - 7

, then evaluate: [3 MARKS]

(i)

α^{2} + β^{2}

\frac{α}{β} + \frac{β}{α}

If $α, β, γ$ are the zeros of the polynomial $2 x^{3} + x^{2} - 13 x + 6$ then $α β γ = ?$

(a) -3 (b) 3 (c) $\frac{- 1}{2}$ (d) $\frac{- 13}{2}$

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