If fx-4x-5- gx-x2 and hx-1x- then fghx is

The correct option is A 4(x 5) Given that g(x)=x^2 and h(x)=1x g(h(x))=(1x)^2=1x^2 Now put the value so obtained in f(x) f(x)=4 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Auto Protolysis of Water

if fx=4x-5,...

Question

if $f (x) = 4 x - 5, g (x) = x^{2}$ and $h (x) = \frac{1}{x}$ , then $f (g (h (x)))$ is

\frac{4}{(x - 5)}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{(4 x - 5)^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(\frac{x}{4} - 5)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(\frac{4}{x^{2}})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

f (x) = 2, g (x) = x^{2}, h (x) = 2 x, \forall x \in R

(f (g (h (x))))

f (x) = \frac{2}{x - 3}

g (x) = \frac{x - 3}{x + 4}

h (x) = - \frac{2 (2 x + 1)}{x^{2} + x - 12}

lim x \to 3 [f (x) + g (x) + h (x)]

f (x) = \frac{2}{x - 3}, g (x) = \frac{x - 3}{x + 4}

h (x) = \frac{- 2 (2 x + 1)}{x^{2} + x - 12}

lim x \to 3 [f (x) + g (x) + h (x)]

f (x) = c o t^{- 1} (\frac{3 x - x^{3}}{1 - 3 x^{2}}), g (x) = c o s^{- 1} (\frac{1 - x^{2}}{1 + x^{2}})

f (x) = g (x)

x = \frac{\sqrt{25 - 10 \sqrt{5}}}{5}

s i n 18^{o} = \frac{\sqrt{5} - 1}{4}

f (x) = \frac{3}{x - 2} - \frac{1}{x + 3}

g (x) = \frac{x^{2} - 4 x + 19}{x^{2} + x - 6}

f (x) = g (x)

x =

Join BYJU'S Learning Program