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Derivative

If f(x) and g...

Question

If f(x) and g(x) have equal derivatives, then f(x) - g(x) is a ___________ function

Constant

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Identify

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Even

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Odd

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Solution

The correct option is A
Constant

$f^{1} (x) = g^{1} (x) \Rightarrow f (x) + c_{1} = g (x) + c_{2} ∴ f (x) - g (x) = c_{2} - c_{1} = c o n s t a n t$

Suggest Corrections

Similar questions

R \to R

sin x cos y [f (2 x + 2 y) - f (2 x - 2 y)] = cos x sin y [f (2 x + 2 y) + f (2 x - 2 y)]

f^{'} (0) = \frac{1}{2}

f^{'} (x) = g (x) {(x - a)}^{2}

g (a) \neq 0

x = a,

f (x) = a^{x} (a > 0)

f (x) = f_{1} (x) + f_{2} (x)

f_{1} (x)

f_{2} (x)

f_{1} (x + y) + f_{1} (x - y)

f (x, y) = f (2 x + 2 y), (2 y - 2 x)

\forall x, y \in R

g

g (x) = f (2^{x}, 0)

g (x)

f

(a, b)

lim x \to a^{+} f (x) \to \infty

lim x \to b^{-} f (x) \to - \infty

f^{'} (x) + f^{2} (x) \geq - 1

a < x < b

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