Consider the following question.
Find the value of “k” we get.
$ f(x)=\left( \begin{align}
2x+2−164x−16,ifx≠2
k,ifx=2
\end{align} \right)\,\,\, $
limx→22x+2−164x−16=limx→24x−164x−16
=1
k=1
function is continuous.
Hence, this is the required answer.
.