Iff(x)={x2−3,2<x<32x+5,3<x<4, the equation whose roots are limx→3−f(x) and limx→3+f(x)is
A
x2 - 12x + 36 = 0
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B
x2 - 26x + 66 = 0
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C
x2 - 17x + 66 = 0
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D
x2 - 22x + 121 = 0
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Solution
The correct option is C x2 - 17x + 66 = 0
f(x)={x2−3,2<x<32x+5,3<x<4 ∴limx→3−f(x)=limx→3−(x2−3)=6 and limx→3+f(x)=limx→3+(2x+5)=11 Hence, the required equation will be x2 - (sum of roots)x + (Products of roots) = 0