Iff(x)={x2−3,2<x<32x+5,3<x<4, the equation whose roots are limx→3−f(x) and limx→3+f(x)is
A
x2−12x+36=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
x2−26x+66=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x2−17x+66=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
x2−22x+121=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Cx2−17x+66=0
f(x)={x2−3,2<x<32x+5,3<x<4 ∴limx→3−f(x)=limx→3−(x2−3)=6
and limx→3+f(x)=limx→3+(2x+5)=11
Hence, the required equation will be x2 - (sum of roots)x + (Products of roots) = 0