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Question

If f(x)=∣ ∣ ∣12(x1)3(x1)(x2)x1(x1)(x2)(x1)(x2)(x3)x(x1)x(x1)(x2)x∣ ∣ ∣ then f(41)is

A
41
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B
41
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C
0
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D
Noneofthese
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Solution

The correct option is A 41
f(x)=∣ ∣ ∣12(x1)3(x1)(x2)x1(x1)(x2)(x1)(x2)(x3)x(x1)xx(x1)(x2)∣ ∣ ∣f(x)=(x1)∣ ∣ ∣123(x1)(x2)(x1)(x2)(x1)(x2)(x3)xxx(x1)(x2)∣ ∣ ∣=x(x1)2(x2)∣ ∣123(x1)(x2)(x3)111∣ ∣=x(x1)2(x2)[(1)(4)+(3)]=x(x1)2(x2)(0)=0f(x)=0f(41)=0

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