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Byju's Answer
Standard XII
Mathematics
Integration of a Determinant
If f(x)= 1 ...
Question
If
f
(
x
)
=
∣
∣ ∣
∣
1
2
x
3
x
2
3
a
27
1
3
9
∣
∣ ∣
∣
and
∫
3
0
f
(
x
)
d
x
=
0
, then a is equal to
A
3
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B
6
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C
9
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D
any real number
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Solution
The correct option is
D
any real number
∫
3
0
f
(
x
)
d
x
=
∣
∣ ∣ ∣
∣
∫
3
0
d
x
∫
3
0
2
x
d
x
∫
3
0
3
x
2
d
x
3
a
27
1
3
9
∣
∣ ∣ ∣
∣
=
∣
∣ ∣
∣
3
9
27
3
a
27
1
3
9
∣
∣ ∣
∣
∫
3
0
f
(
x
)
d
x
=
0
∴
a
∈
any real number.
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Similar questions
Q.
If
f
(
x
)
=
∣
∣ ∣
∣
1
2
x
3
x
2
3
a
27
1
3
9
∣
∣ ∣
∣
and
∫
3
0
f
(
x
)
d
x
=
0
, then a is equal to
Q.
If
f
(
x
)
=
∣
∣ ∣
∣
1
2
x
3
x
2
3
a
27
1
3
9
∣
∣ ∣
∣
and
∫
3
0
f
(
x
)
d
x
=
0
, then a is equal to
Q.
If
f
(
x
+
y
)
=
f
(
x
)
+
f
(
y
)
+
c
, for all real
x
and
y
and
f
(
x
)
is continuous at
x
=
0
and
f
′
(
0
)
=
1
then
f
′
(
x
)
equals to
Q.
If
f
(
x
)
be a polynomial of degree
8
such that
f
(
x
)
=
f
(
4
−
x
)
∀
x
ϵ
R
,
f
(
x
)
has
6
distinct real and equal roots then sum of roots of
f
(
x
)
=
0
is
A
. Then the number
A
is:
Q.
Statement 1 : If
f
(
x
)
=
a
x
2
+
b
x
+
c
, where
a
>
0
,
c
<
0
and
b
∈
R
, then roots of
f
(
x
)
=
0
must be real and distinct .
Statement 2 : If
f
(
x
)
=
a
x
2
+
b
x
+
c
,
where
a
>
0
,
b
∈
R
,
b
≠
0
and the roots of
f
(
x
)
=
0
are real and distinct, then
c
is necessarily negative real number .
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