If f(x)=∣∣
∣
∣
∣∣cosxex22xcos2x2x2secxsinx+x312x+tanx∣∣
∣
∣
∣∣, then the value of ∫π2−π2(x2+1)(f(x)+f′′(x))dx, is equal to
A
1
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B
−1
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C
2
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D
none of these
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Solution
The correct option is D none of these Clearly f(x) is an odd function as, f(−x)=−f(x) So f′′(x) will also be odd function and x2+1 is an even function. Hence required integral will vanish.