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Question

If f(x)=∣ ∣ ∣ ∣cosxex22xcos2x2x2secxsinx+x312x+tanx∣ ∣ ∣ ∣, then the value of π2π2(x2+1)(f(x)+f(x))dx, is equal to

A
1
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B
1
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C
2
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D
none of these
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Solution

The correct option is D none of these
Clearly f(x) is an odd function as, f(x)=f(x)
So f′′(x) will also be odd function and x2+1 is an even function.
Hence required integral will vanish.

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