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Question

If f(x)=∣ ∣sin xsin asin bcos xcos acos btan xtan atan b∣ ∣,

where 0<a<b<π2
then the equation
f(x)=0 has in the interval (a,b)


A

Atleast one root

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B

Atmost one root

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C

No root

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D

None of these

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Solution

The correct option is A

Atleast one root


Here f(a)=∣ ∣sin asin asin bcos acos acos btan atan atan b∣ ∣=0.Also f(b)=0.
Moreover, as sin x, cos x and tan x are continuos and differentiable in (a, b) for 0 < a < b < π2, therefore f(x) is also continuos and differentiable in [a, b]. Hence, by Rolle's theorem, there exists atleast one real number c in (a, b) such that f ' (c) = 0.
Hence (a) is the correct answer.


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