If fx-x2 2 5 3x 3 7 2 0 9 - then the value of f-1 is-

We have, f(x)= x^2 amp; 2 nbsp; amp; 5 nbsp; nbsp;3x amp; 3 amp; 7 nbsp; nbsp;2 amp; 0 nbsp; amp; 9 nbsp; ⇒ f' (x)= 2x a ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Identity Matrix

If fx=x2 2 ...

Question

If $f (x) = ∣ ∣ ∣ ∣ \begin{matrix} x^{2} & 2 & 5 3 x & 3 & 7 2 & 0 & 9 \end{matrix} ∣ ∣ ∣ ∣,$ then the value of $f^{'} (1)$ is:

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

∣ ∣ ∣ ∣ \begin{matrix} x^{2} + 3 x & x + 1 & x - 2 x - 1 & 1 - 2 x & x + 4 x + 3 & x - 4 & 3 x \end{matrix} ∣ ∣ ∣ ∣ = A x^{4} + B x^{3} + C x^{2} + D x + ϱ

ϱ

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & 3 x - 1 & - x + 3 2 x + 1 & 2 + x^{2} & x^{3} - 3 x - 3 & x^{2} + 4 & 3 x \end{matrix} ∣ ∣ ∣ ∣ ∣ = a_{0} + a_{1} x + a_{2} x^{2} + . . . + a_{7} x^{7}

a_{0}

f (x) = 2 x^{3} - 6 x^{2} + 4 x - 5

g (x) = 3 x^{2} - 9

f (1) + g (- 2)

Δ = ∣ ∣ ∣ ∣ \begin{matrix} x - 3 & 2 x + 1 & 2 3 x + 2 & x + 2 & 1 5 x + 1 & 5 x + 4 & 5 \end{matrix} ∣ ∣ ∣ ∣

Δ

f (x) = \frac{x^{2}}{2}

0 \leq x \leq 1

f (x) = 2 x^{2} - 3 x + (3 / 2)

1 \leq x \leq 2

f^{''} (x)

Join BYJU'S Learning Program