If $f (x) = cos (tan x)$ , then $f^{'} (x)$ at $x = e$ is

- sin (tan e) \times {sec}^{2} e

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- (tan e) \times {sec}^{2} e

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{sec}^{2} e

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None of these

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Solution

The correct option is C $- sin (tan e) \times {sec}^{2} e$

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A

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