If f(x)=11−x,x≠0,1 then the graph of the function y=f[f{f(x)}] for x>1 is
A
a straight line
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B
a circle
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C
an ellipse
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D
a pair of straight lines
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Solution
The correct option is A a straight line Given f(x)=11−x ⇒f{f(x)}=11−f(x)=11−11−x=1−x1−x−1=1−1x ∴f[f{f(x)}]=11−f{f(x)}=11−1+1x=x, which is a straight line.