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Chain Rule of Differentiation

If fx=1ax2+...

Question

If $f (x) = \frac{1}{a x^{2} + b c + c}$ , then the value of $f^{'} (x)$ =

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Solution

$f (x) = \frac{1}{a x^{2} + b x + c} f^{^{'}} (x) = - \frac{2 a x + b}{{(a x^{2} + b x + c)}^{2}}$

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\frac{1}{2}

and 0 are the zeroes of the polynomial

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