If fx-1-x-2-2x-4-1-x-2-2x-4 for x - 2- then f11-

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Standard XII

Mathematics

Definition of Functions

If fx=1√x+2...

Question

If $f (x) = \frac{1}{\sqrt{x + 2 \sqrt{2 x - 4}}} + \frac{1}{\sqrt{x - 2 \sqrt{2 x - 4}}}$ for $x > 2$ , then $f (11) = ?$

7 / 6

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5 / 6

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6 / 7

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5 / 7

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Solution

The correct option is C $6 / 7$
correct answer is (C)

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Similar questions

Q. If

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} - 2 x + 3 & 7 x + 2 & x + 4 2 x + 7 & x^{2} - x + 2 & 3 x 3 & 2 x - 1 & x^{2} - 4 x + 7 \end{matrix} ∣ ∣ ∣ ∣ ∣ = a x^{6} + b x^{5} + c x^{4} + d x^{3} + e x^{2} + f x + g

the value of

g

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$