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Extrema

If fx=1x2-1...

Question

If $f (x) = \frac{1}{x^{2} - 17 x + 66}$ then points of discontinuity of $f (\frac{2}{x - 2})$ is/are at

A

x = 2

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B

x = \frac{7}{3}

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C

x = \frac{24}{11}

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D

N o n e o f t h e s e

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Solution

The correct options are
B $x = \frac{7}{3}$
C $x = \frac{24}{11}$

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Similar questions

f (x) = \frac{1}{x^{2} - 17 x + 66}

f (\frac{2}{x - 2})

is discontinuous at

x =

f (x) = \frac{1}{x^{2} - 17 x + 66}, t h e n f (\frac{2}{x - 2})

is discontinuous at x=

f (x) = \frac{1}{x^{2} - 17 x + 66}

f (\frac{2}{x - 2})

is continuous at R except

x =

f (x) = \frac{1}{(x - 1) (x - 2)} a n d g (x) = \frac{1}{x^{2}}

, then points of discontinuity of f(g(x)) are

Q. The point(s) of discontinuity of the function

f (x) = \frac{1}{x^{2} - 3 | x | + 2}

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