Question

If $f\left(x\right)=\frac{1}{x}$ and $g\left(x\right)=x^3+1$, then the number of solution(s) of $f\left(x\right)=g\left(x\right)$ is

Answer 1

The graph of $y=x^3$ is


Now, to draw the graph of $g\left(x\right)$, we shift the above graph vertically upward by $1$ unit, so the graphs are


Hence, the number of solutions is $2.$