If fx - 4x - x41 - 4x3 and gx - ln 1 - x1 - x - then what is the value of f- g e - 1e - 1 equal to-

The correct option is B 1 g(e 1e+1)=log_e{1+(e 1e+1)1 (e 1e+1)}=log_e(2e2)=log_ee=1 ∴ fog(e 1e+1)=f(g(e 1e+1))=f(1)=4+11+4=1 ...

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Definition of Functions

If fx = 4x ...

Question

If $f (x) = \frac{4 x + x^{4}}{1 + 4 x^{3}}$ and $g (x) = ln (\frac{1 + x}{1 - x})$ , then what is the value of $f \cdot g (\frac{e - 1}{e + 1})$ equal to?

2

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1

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0

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\frac{1}{2}

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Solution

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Similar questions

f (x) = 4 x^{3} - x^{2} - 2 x + 1

g (x) = [\begin{matrix} M i n f (t) : 0 \leq t \leq x; & 0 \leq x \leq 1 3 - x; & 1 < x \leq 2 \end{matrix}]

g (\frac{1}{4}) + g (\frac{3}{4}) + g (\frac{5}{4})

f (x) = ln \frac{1 + x}{1 - x}

g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}

f [g (x)]

x = 1 + \sqrt{2}

x^{4} - 4 x^{3} + 4 x^{2}

f (x) = {log}_{e} (\frac{1 + x}{1 - x}), g (x) = \frac{3 x + x^{3}}{1 + 3 x^{2}}

g o f (t) = g (f (t))

g o f (\frac{e - 1}{e + 1})

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