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Domain

If x=x2-3 x+1...

Question

If $f (x) = \frac{x^{2} - 3 x + 1}{x^{2} + 4 x + 3},$ then domain of $f (x)$ is

A

R - {- 1, 3}

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B

R

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C

R - {1, 3}

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D

R - {- 1, - 3}

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Solution

The correct option is D $R - {- 1, - 3}$
$f (x) = \frac{x^{2} - 3 x + 1}{x^{2} + 4 x + 3}$
$= \frac{x^{2} - 3 x + 1}{(x + 1) (x + 3)}$

Since, $f (x)$ is not defined at $x = - 1, - 3.$
Therefore, domain $= R - {- 1, - 3}$

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