If fx - x2 - 5x - 6x -2- x - 2- then f3 is equal to

The correct option is D 0 Given, f(x)= x ^ 2 5x+6 x 2 , #160;x≠ 2 So, f(x) has a finite real value. ∴ #160;f(3)= 3 ^ 2 5× 3+6 3 2 ...

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Introduction

If fx = x2 ...

Question

If $f (x) = \frac{x^{2} - 5 x + 6}{x - 2}, x \neq 2$ , then $f (3)$ is equal to

8

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6

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Similar questions

f (x) = x^{2} - 5 x + 6

\frac{x^{3} - 6 x^{2} + 10 x - 2}{x^{2} - 5 x + 6} = f (x) + \frac{A}{x - 2} + \frac{B}{x - 3}

f (x) =

A, B

f (x) = {\begin{matrix} 2 - | x^{2} + 5 x + 6 |, x \neq - 2 a^{2} + 1, x = - 2 \end{matrix}

a

f (x)

x = - 2

f (x) = 5 x - x^{2}

f (x) = 6

x =

f : R \to R

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \frac{λ | x^{2} - 5 x + 6 |}{μ (5 x - x^{2} - 6)}, & x < 2 e^{\frac{tan (x - 2)}{x - [x]}}, & x > 2 μ, & x = 2 \end{matrix}

[x]

x

f

x = 2,

λ + μ

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