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Question

If f(x)=asinxbx+cx2+x32x2n(1+x)2x3+x4, when x0 and f(x) is continuous at x=0, find value of 200×f(0)

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Solution

limx0a[xx36+x5120.......]bx+cx2+x32x2[xx22+x33.........]2x3+x4
=limx0(ab)x+cx2+[1a6]x3+ax5120+.....2x53x62+......
for this limit to be exist, ab=0,c=0, & 1a6=0
a=b=6 & c=0.
then f(0)=6120.32=340200f(0)=15

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