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Definition of a Determinant

If fx=e x...

Question

If $f (x) = e$ $^{x}$ $g (x),$
$g (0) = 1, g^{'} (0) = 3$ , then $f^{'} (0)$ is

0

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4

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3

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7

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Solution

The correct option is D $4$
$f^{'} (x) = e^{^{x}} g (x) + e^{^{x}} g^{'} (x)$
For x=0:
$f^{'} (0) = g (0) + g^{'} (0) = 4$

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