For solving these types of integral which has ex multiplied with some other functions in the integrand we should check whether the function is of the form ∫ex(f(x)+f′(x)]dx
because
∫ex(f(x)+f′(x)]dx=exf(x)+C.
Now Looking at this integral we see that if f(x)=sin(lnx),
⇒f′(x)=cos(lnx)x,
thus our integral reduces to the form ∫ex(f(x)+f′(x)]dx ⇒∫ex(sin(lnx)+cos(lnx)x]dx
=exsin(lnx)+C
Now, the constant of integration is assunmed to be zero.
⇒F(x)=exsin(lnx)
F(1)=e1sin(ln1)⇒F(1)=e×0=0