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Question

If F(x)=ex (sin(lnx)+cos(lnx)x]dx,then F(1) (assume the constant ofintegration to be 0) is



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Solution

For solving these types of integral which has ex multiplied with some other functions in the integrand we should check whether the function is of the form ex(f(x)+f(x)]dx
because
ex(f(x)+f(x)]dx=exf(x)+C.
Now Looking at this integral we see that if f(x)=sin(lnx),
f(x)=cos(lnx)x,
thus our integral reduces to the form ex(f(x)+f(x)]dx ex(sin(lnx)+cos(lnx)x]dx
=exsin(lnx)+C
Now, the constant of integration is assunmed to be zero.
F(x)=exsin(lnx)
F(1)=e1sin(ln1)F(1)=e×0=0

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