If f x - f x -4- f x -2- f x -6 - x - R and a -0 and f x is periodic- then period of f x - isA- 1000B- 100C- 10000D- 10

The correct option is A 1000f(x)+f(x+4)=f(x+2)+f(x+6)...1(i). Replacing x by x + 2 in equation (i), we get f(x+2)+f(x+6)=f(x+4)+f(x+8) . . . . .(ii) Add ...

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Standard IX

Mathematics

Period of a Function

If f x + f x ...

Question

If $f (x) + f (x + 4) = f (x + 2) + f (x + 6) \forall x ϵ R a n d a > 0$ and and f(5)=10, then ∑r=1100f(5+8r) equal to

1000

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100

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10000

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If f(x)+f(x+4)=f(x+2)+f(x+6)∀xϵ R and a>0 and and f(5)=10, then ∑r=1100​f(5+8r) equal to

If $f (x) + f (x + 4) = f (x + 2) + f (x + 6) \forall x ϵ R a n d a > 0$ and and f(5)=10, then ∑r=1100f(5+8r) equal to