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Question

If f(x)=1(x1)(x2) and g(x)=1x2, then points of discontinuity of f(g(x)) are

A
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Solution

The correct option is B
f(g(x))=1(1x21)(1x22)=x4(1x2)(12x2)f(g(x)) is discontinuous at x=±1,x=±12 and x=0
Since, g(x) is discontinuous at x=0

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