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Question

If f(x) = 2x27x+35x212x9 , then limx3f(x) is

A
-1/3
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B
5/18
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C
0
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D
2/5
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Solution

The correct option is B 5/18
limx3f(x)=limx32x27x+35x212x9(00)
Apply L'Hospital's rule

= limx34x710x12

= 518

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