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Question

If f(x)=axx+1,x1 . then, for what value of a is f(f(x)) = x

A
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B
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C
1
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D
-1
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Solution

The correct option is D -1

f(f(x))=af(x)f(x)+1=a(azz+1)(azz+1+1)=a2.xax+x+1

x=a2.x(a+x)x+1 or x((a+1)x+1a2)=0

Or (a+1)x2+(1a2)x=0. This should hold for all x.

a+1=0,1a2=0, a=1.


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