If f(x) , g(x) and h(x) are three polynomials of degree 2 and ϕ(x)=∣∣
∣
∣∣f(x)g(x)h(x)f′(x)g′(x)g′(x)f′′(x)g′′(x)h′′(x)∣∣
∣
∣∣ , then ϕ′(x) is
A
a one degree polynomial
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B
a three degree polynomial
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C
a two degree polynomial
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D
a constant
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Solution
The correct option is D a constant Using the concept of derivative of determinants, ϕ′(x)=∣∣
∣
∣∣f′(x)g′(x)h′(x)f′(x)g′(x)h′(x)f′′(x)g′′(x)h′′(x)∣∣
∣
∣∣+∣∣
∣
∣∣f(x)g(x)h(x)f′′(x)g′′(x)h′′(x)f′′(x)g′′(x)h′′(x)∣∣
∣
∣∣+∣∣
∣
∣∣f(x)g(x)h(x)f′(x)g′(x)h′(x)f′′′(x)g′′′(x)h′′′(x)∣∣
∣
∣∣ =0+0+∣∣
∣
∣∣f(x)g(x)h(x)f′(x)g′(x)h′(x)000∣∣
∣
∣∣ =0 Hence, ϕ′(x) is a constant.